from typing import TypeVar, Callable, Union, Protocol, Any class SupportsLessThan( Protocol ): def __lt__( self, other: Any ) -> bool: ... K = TypeVar( 'K', bound = SupportsLessThan ) V = TypeVar( 'V' ) W = TypeVar( 'W' ) # ----- %< ----- %< ----- # Write a function ‹merge_dict› which takes these 3 arguments: # # • a ‹dict› instance, in which some keys are deemed equivalent: # the goal of ‹merge_dict› is to create a new dictionary, where # all equivalent keys have been merged; keys which are not # equivalent to anything else are left alone (though the single # value is still passed through ‹combine›), # • a ‹list› of ‹set› instances, where each ‹set› describes one set # of equivalent keys (the sets are pairwise disjoint), and # finally, # • a function ‹combine› which takes a ‹list› of values (not a set, # because we may care about duplicates): ‹merge_dict› will pass, # for each set of equivalent keys, all the values corresponding to # those keys into ‹combine›. # # In the output dictionary, create a single key for each equivalent # set: # # • the key is the «smallest» of the keys from the set which were # actually present in the input ‹dict›, # • the value is the result of calling ‹combine› on the list of # values associated with all the equivalent keys in the input # ‹dict›. # # Do not modify the input dictionary. def merge_dict( dict_in: dict[ K, V ], equiv: list[ set[ K ] ], combine: Callable[ [ list[ V ] ], W ] ) \ -> dict[ K, W ]: pass # ----- >% ----- >% ----- def test_a() -> None: combine = lambda x : sum( x ) dict_in = { 1: 1, 2: 2, 3: 3, 4: 4, 5: 1, 6: 2, 7: 3 } eq = [ set( [ 1, 3, 5, 7 ] ), set( [ 2, 4, 6 ] ) ] dict_orig = dict_in.copy() assert merge_dict( dict_in, eq, combine ) == { 1: 8, 2: 8 } assert dict_in == dict_orig def test_b() -> None: def combine( x: list[ str ] ) -> int: return sum( [ len( s ) for s in x ] ) dict_in = { 2: 'two', 3: 'three', 6: 'two', 1: 'one', 9: 'woo' } eq = [ set( [ 2 ] ), set( [ 3, 6, 1 ] ) ] dict_orig = dict_in.copy() assert merge_dict( dict_in, eq, combine ) == { 2: 3, 1: 11, 9: 3 } assert dict_in == dict_orig def test_c() -> None: combine = lambda x : "".join( [ str( y ) for y in x ] ) dict_in : dict[ Union[ int, str ], Union[ int, str ] ] dict_in = { 1: 9, 8: "eek", "ef": 22 } eq: list[ set[ Union[ str, int ] ] ] = [] dict_orig = dict_in.copy() expect = { 1: "9", 8: "eek", "ef": "22" } assert merge_dict( dict_in, eq, combine ) == expect assert dict_in == dict_orig def test_d() -> None: from copy import deepcopy dict_in = { "ab": { 7: 33, 9: 1, 13: 45 }, "abcde": { 3: 9, 0: 5, -1: 4 }, "foo": { 1: 3, 91: 3, 4: 3, 5: -1, 8: 4 }, "val": { 6: 7 } } eq_out = [ set( [ "ab", "abcde", "val" ] ) ] eq_in = [ set( [ 1, 91, 8, 6 ] ), set( [ 3, 7, 9, -1 ] ), set( [ 0 ] ) ] dict_orig = deepcopy( dict_in ) # list of dictionaries into one dictionary def flatten( x: list[ dict[ K, V ] ] ) -> dict[ K, V ]: d = {} for dic in x: d.update( dic ) return d combine = lambda x : merge_dict( flatten( x ), eq_in, lambda y : sum( y ) ) expect = { "ab": { 13: 45, -1: 47, 0: 5, 6: 7 }, "foo": { 1: 10, 4: 3, 5: -1 } } res = merge_dict( dict_in, eq_out, combine ) assert res == expect, res assert dict_in == dict_orig if __name__ == "__main__": test_a() test_b() test_c() test_d()