From the previous exercise, take the following table: Table 1 with fingerprints: Table 1 -OH -Cl -NO[2] -CH[3] -COOH 2,4,6-trinitrophenol 1 0 0 1 0 1 0 0 2,3-dinitrophenol 1 0 0 1 0 1 0 0 3-hydroxybenzaldehyd 1 0 0 1 0 0 0 0 2,4,6-trimethylphenol 1 0 0 1 0 0 1 0 a) Count Tanimoto coefficient for pairs: · 2,4,6-trinitrofenol and 2,3-dinitrofenol: · 2,4,6-trinitrofenol and 3-hydroxybenzaldehyd: b) Fill values of Tanimoto coefficient into the table: Table 2 2,4,6-trinitrophenol 2,3-dinitrophenol 3-hydroxy-benzaldehyd 2,4,6-trimethylphenol 2,4,6-trinitrophenol 2,3-dinitrophenol 3-hydroxybenzaldehyd 2,4,6-trimethylphenol c) Which pair(s) have the Tanimoto coefficient the lowest and the highest? d) Count the Cosine coefficient for the pairs: · 2,4,6-trimethylphenol and 2,3-dinitrophenol: · 2,4,6-trimethylphenol and 3-hydroxybenzaldehyd: e) Count (binarny) Euclid distance for pairs: · 2,4,6-trinitrophenol and 2,3-dinitrophenol: · 2,4,6-trinitrophenol and 3-hydroxybenzaldehyd: 1. Do consensus fingerprints for fingerprints from Table 1 (use OR): Table 1 -NO[2] -OH -COOH -Cl -CH[3] 2,4,6-trinitrophenol 2,3-dinitrophenol 3-hydroxybenzaldehyd 2,4,6-trimethylphenol 2. Use the charges on atoms O and H from the previous exercise: Table with charges: Table 3 Charge on O (from OH skupiny) Charge from H (from OH skupiny) 2,4,6-trinitrophenol -0,5690 0,5670 2,3-dinitrophenol -0,6110 0,4640 3-hydroxybenzaldehyd -0,6910 0,4060 2,4,6-trimethylphenol -0,7140 0,3670 a) Create a descriptor space graph in Excel, specifically: Put a charge on the x-axis at O, a charge on the y-axis at H. Show a graph that shows the X and Y points. Note: If you are not familiar with Excel, do the following: Copy the above table into Excel. Label the values of the hubs. Put "Insert" and select "Charts" and select the X,Y chart. b) Count the Euclid distance: · 2,4,6-trinitrophenol and 2,3-dinitrophenol: · 2,4,6-trinitrophenol and 3-hydroxybenzaldehyd: b) Which pair has the biggest Euclid distance? c) Which pair has the lowest Euclid distance? d) Which Euclid distance is more informative? Binary or with real numbers?