2D AND 3D MOTION ANALYSIS
2013
Analysis of the
movement
Pole vault
María Sánchez Aranda
M A S A R Y K U N I V E R S I T Y
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DISTANCE
Taking as a reference the height of the bar (5m, pink line) we will calculate how many pixels
correspond to this distance.
We will use this equation to know the distance between two points:
First we calculate the distance in pixels of the height:
x y
Point 1 25 -1570
Point 2 25 -260
Distance xy = 1310
5 meters → 1310
Once we know the relation between pixels and meters we can calculate the distance of the
step of the jumper:
x y
Point 1 2675 -1950
Point 2 2120 -1945
Distance xy = 555,022
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Now with the rule of 3 we can calculate how many meters are those pixels:
1310 5 x = (5*555,022)/1310
555,022 x
Distance of step (x) = 2,118
SPEED
Now, knowing the distance of step and the time spent on those steps we can calculate the
velocity of the entrance to the last step)
Time = 1,20 seconds
Distance = 6,354 meters (3 steps)
Velocity = 5,295 m/s
ANGLES
To calculate the angles I have used the program Kinovea, which helps you to realize good video
analysis. It can calculate the angles, you just have to point the centre of the angle and it gives
you the number.
I have calculated the angles in the moment of the running, of the last step and of the invert.
Running
Here we can see the different angles during the running in the step before the last one.
First of all, we can observe that the angle of the trunk is more than 90°. If it
was a speed running like 100m it would be a bad measure because the
trunk would be too backwards, but in the pole vault it is perfect because we
are talking about the previous step to the last, so you have to open a space
between your hands and your trunk to have a better position during the last
step.
Next two photos are about the legs. We can say that their position is quite good because the
front leg, the knee, is quite up, so it is perfect to have more space to push for the next step,
and in the back leg we can see that has finish the impulse and it is starting to go forward.
v = e/t = 6.354/1.20 = 5,295 m/s
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Last step
Here we can see the position of the athlete at the moment of the jump. We can observe that
the back leg is quite stretched. This is good because it means that he has pushed at the right
moment to go forward. The front leg is also in a very good position because it helps him to go
forward. On the other hand, the angle of the arms should be a little bit more wide, because it
would help more to the athlete.
Invert
The angle of the perfect invert is 180°, here this athlete just arrives to 155°
but it is also quite good, because it will help him perfectly to go very high.
We can also see that he is inverted in the perfect moment, just a little bit
before the pole is completely straight. Being in that position at that time is
great because when the pole goes straight he will start to help with his
arms and start turning to go the bar in ventral position.