Decide if the 2 sets of data belong to the same population:																	
																	
set1	set2																
16.38	16.84		Grubb´s test:														
19.15	15.46		H0 = There is no outlier in the data set 1.									H0 = There is no outlier in the data set 2.					
19.1	14.41		Ha = There is one outlier in the data set 1.									Ha = There is one outlier in the data set 2.					
19.28	18.1																
19.12	16.99		Max value:	19.28		T (max)=	0.640528401						Max value:	18.1		T (max)=	 1.58505   
18.85	15.11		Min value:	12.45		T (min)=	2.576242909						Min value:	14.41		T (min)=	 1.20201   
18.1	15.1		Mean:	17.92		critical=	2.29						Mean:	16.00		critical=	2.02
19			St. dev.:	2.123246989									St. dev.:	 1.32398 			
17.77						H0 is rejected as calculated T (min) value is higher than critical value.										H0 is accepted as both calculated T values are smaller than critical value.	
12.45						"Therefore, the value 12,45 is an outlier."										"Therefore, there are no outliers in the data set 2."	
																	
																	
F-test:							T-test:	H0 = the means of the 2 data sets are practicallz equal									
							dof=	14		Pool variance=	1.274688662						
9	7	.=N					T=	4.440190496									
0.9160	1.7529	.=variance					Tcrit2=	2.144786688									
18.53	16.00	.=mean															
							H0 is rejected as the calculated T value is higher than the critical value.										
H0 = both variances are equal							"Therefore, there is a difference between the means of the 2 data sets, therefore, they do not belong to the same population."										
F=	1.913621262																
Fcrit2=	5.599623005																
H0 is accepted as the calculated F value is lower that critical value.																	
The variances are equal.