1 Acids Andreas Libau (Libavius) (1540-1616) Gerber – prepared HNO3, HCl and aqua regia (from H2SO4 and salts, isolated citric, acetic, and tartaric acids Libavius - prepared HCl and aqua regia (dissolves Au) The world highest tonnage per annum chemical commodity: H2SO4 Gerber - Jabir ibn Hayyan (721-815) 2 Acids R. Boyle (1627 - 1691): changes of color of litmus L. Lavoisier (1743-1794) : Oxygenium = acid forming Oxides of nonmetals reacts with water to acids H. Davy (1779-1829) J. Liebig (1803-1873) Hydrogen is released during reactions of acids with metals = H governs acidic properties 3 Arrhenius Theory of Acids and Bases Svante Arrhenius (1859-1927) Acids: Taste acidic Release H+ in aqueous soln. Reacts with base metals with release of H2 K, Ca, Na, Mg, Al, Zn, Fe, Ni, Sn, Pb Color litmus red (R. Boyle) Neutralize bases Bases: Taste bitter Release OH− in aqueous soln. Color litmus blue Neutralize acids 4 Strong and Weak Arrhenius Acids Strong Acids : completely ionized in water (100% dissociated) HNO3 → H+ (aq) + NO3 - (aq) HCl, HNO3, H2SO4, HClO4, HI, HBr, HClO3, HBrO3, ..... Weak Acids : partially ionized in water (0% < dissoc. degree <100%) CH3CO2H H+ (aq) + CH3CO2 - (aq) Organic acids, H2CO3, H3BO3, H3PO4, H2S, H2SO3, ... 5 Strong Arrhenius Bases Strong Bases : completely ionized in water (100% dissociated) KOH(s) → K+ (aq) + OH- (aq) Alkali metal hydroxides, alkaline earth metal hydroxides, soluble hydroxides No weak bases in Arrhenius theory 6 Brønsted–Lowry Acids and Bases Wider definition, not limited to aqueous solutions Acid = proton donor = Arrhenius acid Base = proton acceptor 7 Proton H+ H+ hydronium H3O+ oxonium Grotthus mechanism – extremely fast H+ movement H9O4 + = [H3O(H2O)3]+ M. Eigen lifetime H3O+ 1 - 4 ps [H3O(H2O)20]+ Protonation of solvent (S) is exothermic H+ + n S → H(S)n + ΔH < 0 8 High Proton H+ Mobility [H3O]+ 9 Brønsted–Lowry Strong and Weak Acids HSO4 - (aq) + H2O H3O+(aq) + SO4 2-(aq) Equilibrium constant of proton dissociation = ionization constant of acid = acid dissociation constant KC = [H3O+] [SO4 2-] / [HSO4 -] [H2O] [H2O] ~ 55.6 M Ka = [H3O+] [SO4 2-] / [HSO4 -] [ ][ ] [ ]− −+ = 4 2 43 . HSO SOOH Ka pKa = −log Ka Water is a reagent and solvent 10 Acid Strength pKa = −log Ka −7HCl 3.2HF −1.75H3O+ 15.57H2O 12.4CF3CH2OH 10.0PhOH 9.2NH4 + 9.1HCN 4.75CH3COOH −10HClO4 15 – 18ROH 35NH3 pKaAcid HA (aq) + H2O H3O+(aq) + A-(aq) Acid Strength increases Strong acids pKa negative [ ][ ] [ ]HA AOH Ka −+ = .3 Weak acids pKa positive NH3 + H2O H3O+(aq) + NH2 -(aq) 11 Acid Strength and ΔG ΔG = −RT ln Ka = 2.3 RT pKa HA (aq) + H2O H3O+(aq) + A-(aq) Ka = [H3O+] [A-] / [HA] pKa = −log Ka > 1 < 1 Ka ΔGpKa < 0< 0Strong acids > 0> 0Weak acids [ ][ ] [ ]HA AOH Ka −+ = .3 12 Brønsted–Lowry Strong Bases NH3 + H2O H3O+ + NH2 pKa (NH3) > pKa(H2O) CaO + H2O → Ca(OH)2 13 Brønsted–Lowry Weak Bases NH3(aq) + H2O NH4 +(aq) + OH− (aq) K = [NH4 +] [OH- ] / [NH3] [H2O] Kb = [NH4 +] [OH- ] / [NH3] base dissociation constant pKb = −log Kb Equilibrium constant of base protonation by water = ionization constant of base = base dissociation constant 14 Brønsted–Lowry Weak Bases Methylamin CH3NH2 + H2O CH3NH3 + + OH- 4 23 33 104.4 ][ ]][[ − −+ == x NHCH OHNHCH Kb pKb = −logKb 15 Lewis Acids and Bases R N R R + F B FF R N R R F B F F Lewisovabaze Lewisovakyselina Lewis Acids – acceptors of electron pair Lewis Bases – donors of electron pair Lewis AcidLewis Base 16 Conjugated Pairs of Acids and Bases H2O(l) + H2SO4(aq) H3O+(aq) + HSO4 -(aq) Strong Acid Weak base Acid Conjugated Base Base Conjugated Acid Strong Base Weak Acid Conjugated pairs of acids and bases are connected by proton exchange 17 Acid-Base Properties of Water Water is amphoteric – behaves as an acid and a base 2 H2O(l) H3O+(aq) + OH-(aq) Autoionization Water is a very weak electrolyte H2O(l) H+(aq) + OH-(aq) KC = [H+][OH-] / [H2O]2 Kw = [H+][OH-] Kw = ion product of water Kw = 1 10-14 M2 [H+] = [OH-] = 1 10-7 M pKw = 14 in pure water at 25 °C and 101.325 kPa 18 pH and pOH Scales pH = − log [H+] [OH-] = 1 10-7 M pOH = − log [1 10-7 ] pOH = 7 [H+] = 1 10-7 M pH = − log [1 10-7 ] pH = 7 in pure water [H+][OH-] = Kw pH + pOH = pKW = 14.00 Constant inaqueous solutions (ionic product of water) pH < 7 Solution is acidic pH = 7 Solution is neutral pH > 7 Solution is basic 1909 S. P. L. Sørensen Beer brewing 19 pH and pOH Scales pH pOH [H+] M [OH-] M 0 14 1.0 10-14 2 12 0.01 10-12 4 10 0.0001 10-10 6 8 10-6 10-8 8 6 10-8 10-6 10 4 10-10 0.0001 12 2 10-12 0.01 14 0 10-14 1.0 20 pH and pOH Scales [H+] [OH-] pH Solution is acidic Solution is basic 10-14 Concentration,M 21 Neutralization H+ + OH- → H2O ΔH = − 56.9 kJ mol−1 H2SO4 + 2 KOH → 2 H2O + K2SO4 H3PO4 + 3 NaOH → 3 H2O + Na3PO4 2 HCl + Mg(OH)2 → 2 H2O + MgCl2 HCl + NaHCO3 → H2O + NaCl + CO2 H3O+(aq) + OH-(aq) → 2 H2O(l) k = 1.4 1011 2 H2O(l) → H3O+(aq) + OH-(aq) k = 2.5 10−5 22 Ka and Kb of Conjugated Pairs NH3(aq) + H2O NH4 + (aq) + OH- (aq) Kb = [NH4 +] [OH- ] / [NH3] basicity constant of NH3 NH4 +(aq) + H2O H3O+ (aq) + NH3(aq) Kw = [H+][OH-] ion product of water Ka = [H3O+] [NH3] / [NH4 +] acidity constant of NH4 + Ka × Kb = [H3O+] [NH3] / [NH4 +] × [NH4 +] [OH- ] / [NH3] = Kw Ka × Kb = Kw 23 Ka and Kb of Conjugated Pairs ]][[ ][ ]][[ ][ ]][[ 23 33 33 23 +− −+ + + = = = HOHK NHCH OHNHCH K NHCH NHCHH K w b a Ka and Kb relationship CH3NH3 + CH3NH2 + H+ CH3NH2 + H2O CH3NH3 + + OHH2O H+ + OHKa × Kb = Kw pKa + pKb = 14 24 Ka and Kw of Water Autoionization 2 H2O(l) H3O+(aq) + OH-(aq) KC = [H3O+] [OH-] / [H2O]2 Kw = [H3O+] [OH-] ionic product pKw = 14 Ka = [H3O+] [OH-] / [H2O] = Kw / [H2O] acidity constant pKa = 15.74 [H2O] = 55.6 mol l−1 Water is a weak acid 25 Ka of Oxonium Cation H3O+(aq) H3O+(aq) + H2O(l) H2O(l) + H3O+(aq) KC = [H3O+] [H2O] / [H3O+] [H2O] Ka = [H3O+] [H2O] / [H3O+] = [H2O] = 55.6 mol l−1 pKa = − 1.75 Oxonium cation is a strong acid 26 pKa of Acids Acidstrengthincr. HA (aq) H+(aq) + A-(aq) [ ][ ] [ ]HA AOH Ka −+ = .3 pKa = −log Ka pKa 27 35NH2 −NH3 15 – 18RO−ROH 15.57HO−H2O 12.4CF3CH2O−CF3CH2OH 10.0PhO−PhOH 9.2NH3NH4 + 9.1CN−HCN 4.75CH3COO−CH3COOH 3.2F −HF −1.75H2OH3O+ −7Cl −HCl −10ClO4 −HClO4 pKaConjug. baseAcid Acidstrengthincr. Conjug. base strength incr. Ka × Kb = Kw pKa + pKb = 14 28 Reaction Equilibrium Reactions are shifted to weak acids and weak bases Strong acids expel weak acids Strong bases expel weak bases PhOH + F − PhO− + HF Weak acid. Weak base Strong base Strong acid Equilibrium shifted to left CH3COOH + NH3 CH3COO− + NH4 + Equilibrium shifted to right 29 Nivelization Effect of Water Acids stronger than H3O+ are completely dissociated in water Basea stronger than HO− are completely protonated in water35NH2 −NH3 15 – 18RO−ROH 15.57HO−H2O 12.4CF3CH2O−CF3CH2OH 10.0PhO−PhOH 9.2NH3NH4 + 9.1CN−HCN 4.75CH3COO−CH3COOH 3.2F −HF −1.75H2OH3O+ −7Cl −HCl −10ClO4 −HClO4 pKaConjug. baseAcid 30 31 pH of Strong Acids and Bases 0.001 M HNO3 → H+ + NO3 [H+] = 0.001 pH = − log[0.001] = 3 0.1 M KOH → K+ + OH[OH-] = 0.1 pOH = − log[0.1] = 1 pH = 14 − pOH = 13 1 10-9 M HCl → H+ + Cl[H+] = 1x10-9 pH = -log(1x10-9) = 9 H2O → H+ + OH- [H+] = 1 10-7 32 pH of Weak Acids 0 0 2 00 ][][ ][ ][ ][][][][ ][][ )log( ][ ]][[ HAKH HA H K cHAHHAHA AH KpK HA AH K a a HA aaa = = =≈−= = −== + + + −+ −+ HA H+ + ApH = ½ pKa − ½ log cHA Starting acid concentration [H+] is very small in weak acids, then [HA] = [HA]0 HA H+ + A- 33 HA H+ + A- )log( ][ ]][[ aaa KpK HA AH K −== −+ xx0.1 – xEquilibrium xx– xChange 000.1Initial HCOO-H+HCOOH 3 52 4 1012.4 107.1 1.0]1.0[107.1 ]1.0[ ]][[ − − − = = ≈−= − = xx xx xx x xx Ka 4.12 10-34.12 10-30.1 pH = − log(4.12 10-3) = 2.39 Solution of 0.1 M HCOOH, Ka = 1.74 10-4 . pH = ? HCOOH H+ + HCOOx very small, then [HA] = [HA]0 pH = ½ pKa − ½ log cHA 34 xx0.01 – xEquilibrium xx– xChange 000.01Initial HCOO-H+HCOOH 3 6442 642 4 1022.1 2 )1076.1(4107.1107.1 2 4 1076.1107.1 107.1 ]01.0[ ]][[ − −−− −− − = −−±− = −±− = −+ = − = xx xxx a acbb x xxxx x x xx Ka 1.22 10-31.22 10-30.01 pH = − log(1.22 10-3) = 2.9 Solution of 0.1 M HCOOH When x comparable to cHA Then quadratic equation 35 Factors Influencing Acid Strength Bond dissociation energy, D(HA) H-A → H· + ·A Ionization energy of H, IE(H) H· → H+ + e− Electron affinity A, EA(A) ·A + e− → A– Proton affinity A− AP(A) H+ + A– → HA Hydratation (solvation) enthalpy H+ + n H2O → H+ (aq) A– + n H2O → A− (aq) HA D(HA) H. + A. IE(H) H+ + e + A. EA(A) H+ + A- AP(A- ) H+ (aq) + A- (aq) ΔH solvatΔHr HA + H2O H+ (aq) + A- (aq) ΔHr 36 Factors Influencing Acid Strength C C O OH H H C C O OCl Cl Cl H+ Me C Me Me O tBuOH pKa = 16 Weak acid Negative charge on O = attracts H+ CH3COOH pKa = 4.75 CCl3COOH pKa = 0.52 Strong acid = low attraction to H+ 37 Factors Influencing Acid Strength H C H H S O OH O F C F F S O OH O pKa = - 2.5 pKa = - 12 38 Acidity along Periods Increases Hydrides = compounds of H with elements The higher the electronegativity, the higher the acidity, the better stabilization of negative charge NaH = basic hydride: Na+ (aq) + H- (aq) + H2O (l) → H2 (g) + Na+ (aq) + OH- (aq) HCl = acidic hydride: H+ (aq) + Cl- (aq) + H2O (l) → H3O+ (aq) + Cl- (aq) 3.215.73555pKa H-FH-OHH-NH2H-CH3Hydride Acidity Increases 39 Acidity along Groups Increases -RSeH−9HBr 7RTeH−9.5HI 10RSH−7HCl 15-16ROH3.2HF pKaHXpKaHX Acidity Increases Bond strength incr 40 Oxyacids Oxyacids = OH groups bound to an electronegative central atom Strong−32 Very strong−83 Weak21 Very weak70 StrengthpKan (O)n Y (OH)m Acidity incr 41 Oxyacids (O)n Y (OH)m •Stabilization of anions by mezomeric effekt (rezonance) •Increasing charge on Y oxidation number of central atom •Lowering of charge density on O electronegativity of central atom •Removal of e. density by other O atoms (-I) Facilitate dissociation of H+ = incr acid strength Y O O Y O O Y O O O Y O O O Acidity incr 42 Oxidation Number of Central Atom −107O3Cl-O-HPerchloric −35O2Cl-O-HChloric 7.531Cl-O-HHypochloric 2.003O Cl-O-HChlorous pKaOx.no.FormulaAcid 43 Electronegativity of Central Atom 10.642.7I-O-HHypoiodic 8.693.0Br-O-HHypobromic 7.533.2Cl-O-HHypochloric pKaElnegE-O-HAcid 44 Oxyacids M-O ionic bond = weak acids (= hydroxides) NaOH Mg(OH)2 Al(OH)3 Si(OH)4 OP(OH)3 O2S(OH)2 O3ClOH Mn+ - O2- - H M-O covalent = strong acids Acidity increases 45 Oxyacids Factors Influencing Acid Strength •oxidation number of central atom •electronegativity of central atom 46 pKa of Bound Water in Metal Complexes M O H H Acidity incr Decreasing ion radius 47 Acidity of Hydrated Cations 0.62.23[Tl(H2O)6]3+ 3.92.16[In(H2O)6]3+ 2.61.90[Ga(H2O)6]3+ 4.91.89[Al(H2O)6]3+ pKaM-O, ÅCation 48 Solutions of Salts Salts of strong acid – strong base HCl + KOH H2O + KCl H+ + Cl- + K+ + OH- H2O + K+ + ClNo effect on pH Neutral Salts of strong acid – weak base - hydrolysis HNO3 + NH3 NH4 + + NO3 - NH4 + + H2O NH3 + H+ Acidic soln pH = 7 − ½ pKb − ½ log c 49 Solutions of Salts NaOH + HF H2O + Na+ + FF- + H2O HF + OHBasic soln NH4 + + H2O + F- + H2O HF + OH- + NH3 + H+ Salts of weak acid – strong base - hydrolysis Salts of weak acid – weak base - hydrolysis pH = 7 + ½ (pKa − pKb) pH = 7 + ½ pKa + ½ log c 50 Buffers 1 M acetic acid (HAc) and 1 M sodium acetate (NaAc) in 1 l of solution. NaAc decreases acidity of HAc. HAc + H2O Ac− + H3O+ Ac− + H2O HAc + HO− Buffer function = keep constant pH 1. Addition of H+ forms new molecules of HAc 2. Addition of OH− forms new molecules of Ac− 3. pH is constant 51 Buffers Weak acid and its salt pH = pKa + log ([A−] / [HA]) Henderson-Hasselbalch eq Weak base and its salt pH = pKa + log ([B] / [BH+]) = 14 − pKb + log ([B] / [BH+]) 52 Acid-Base Equilibria 1. Ion product of water Kw = [H+][OH-] 2. Dissociation constant Ka = [H3O+] [A-] / [HA] 3. Electroneutrality [H3O+] = [A-] + [OH-] 4. Mass balance [HA]0 = [A-] + [HA] 53 Titration – Controlled Acid-Base Reaction Equivalence point = stoichiometric reaction Titration of strong acid (HCl) By strong base (KOH) 54 Titration of Weak Acid by Strong Base pH = ½ pKa − ½ log [HA] pH = pKa pH = salt 55 Titration of Weak Acid by Strong Base HAc + OH- Ac− + H2O Start of titration : pH = ½ pKa − ½ log [HA] Half-way at [A−] = [HA], tj. 50% neutralized (weak acid. + salt): pH = pKa + log ([A−] / [HA]) pH = pKa At equivalence, [A−] = 100 [HA] NEVER [HA] = 0 pH = pKa + log (100 / 1) = pKa + 2 56 Indicators Acid and its conjugated base have different color Phenolphtalein pH = 7.0 8.5 9.4 9.8 12.0 HIn + H2O H3O+ + In- 57 Phenolphtalein C O O C - O O OH O HO - O - 2 H+ + 2 H+ Colorless Red 58 IndikátoryFFMOlitmus 0 7 14 pH Color change pH = pKIN ± 1 59 Indicators HIn + H2O H3O+ + InKIN = [H3O+] [In−] / [HIn] A color change is recognizable if the other form is present in at least 10% amount [H3O+] = KIN ([HIn] / [In−] ) from 10:1 to 1:10 pH = pKIN ± 1 60 Titration of Strong Base by Strong Acid 61 Titration of Weak Base by Strong Acid [B] = [BH+] pH = pKa + log ([B] / [BH+]) = 14 − pKb + log ([B] / [BH+]) = 14 − pKb Equivalence pH = 14 − pKb + log ([1] / [100]) = 14 − pKb − 2 62 63 HSAB = Hard and Soft Acids and Bases Hard Acids Ti4+, Cr3+, Fe3+, Co3+ , H+ Soft Acids Cu+, Ag+, Hg+, Hg2+, Pd2+, Pt2+ Hard Bases NH3, NH2R, N2H4, H2O, OH-, O2-, ROH, RO-, OR2, CO3 2-, SO4 2-, OClO3 -, Cl-, F-, NO3 -, PO4 3-, OCOMe Soft Bases H-, R-, C2H2, C6H6, CN-, CO, SCN-, PR3, P(OR)3, AsR3, SR2, SHR, SR-, I-