HOMEWORK 2 – 2019 Exercise 1. Given the short exact sequence of Abelian groups 0 // A f // B g // C // 0 the following conditions are equivalent: (1) There exists p: B → A such that p ◦ f = idA. (2) There exists q: C → B such that g ◦ q = idC. (3) There are p: B → A and q: C → B such that f ◦ q + q ◦ g = idB. Prove that (3) ⇒ (1) and (2). Exercise 2. For the short exact sequence od chain complexes 0 // A∗ f // B∗ g // C∗ // 0 there is a long exact sequence of homology groups . . . // Hn+1(C∗) ∂∗ // Hn(A∗) f∗ // Hn(B∗) g∗ // Hn(C∗) ∂∗ // Hn−1(A∗) // . . . with the connecting homomorphism ∂∗ defined by the prescription ∂∗([c]) = [a], where ∂c = 0, f(a) = ∂b, g(b) = c. (1) Prove that the definition is independent of the choice of c in the homology class in Hn(C∗). (2) Prove the exactness in Hn(C∗). 1