Tutorial 6—Global Analysis 1. Suppose M = R2 with coordinates (x, y). Consider the vector fields ξ(x, y) = y ∂ ∂x and η(x, y) = x2 2 ∂ ∂y on M. We computed in class their flows and saw that they are complete. Compute [ξ, η] and its flow? Is [ξ, η] complete? 2. Let M be a (smooth) manifold and ξ, η ∈ X(M) two vector fields on M. Show that (a) [ξ, η] = 0 ⇐⇒ (Flξ t )∗ η = η, whenever defined ⇐⇒ Flξ t ◦ Flη s = Flη s ◦ Flξ t , whenever defined. (b) If N is another manifold, f : M → N a smooth map, and ξ and η are f-related to vector fields ˜ξ resp. ˜η on N, then [ξ, η] is f-related to [˜ξ, ˜η]. 3. Suppose αi j for i = 1, ..., k and j = 1, ..., n are smooth real-valued functions defined on some open set U ⊂ Rn+k satisfying ∂αi j ∂xk + αk ∂αi j ∂z = ∂αi k ∂xj + αj ∂αi k ∂z , where we write (x, z) = (x1 , ..., xn , z1 , ..., zk ) for a point in Rn+k . Show that for any point (x0, z0) ∈ U there exists an open neighbourhood V of x0 in Rn and a unique C∞ -map f : V → Rk such that ∂fi ∂xj (x1 , ..., xn ) = αi j(x1 , ..., xn , f1 (x), ..., fk (x)) and f(x0) = z0. In the class/tutorial we proved this for k = 1 and j = 2. 4. Which of the following systems of PDEs have solutions f(x, y) (resp. f(x, y) and g(x, y)) in an open neighbourhood of the origin for positive values of f(0, 0) (resp. f(0, 0) and g(0, 0))? (a) ∂f ∂x = f cos y and ∂f ∂y = −f log f tan y. (b) ∂f ∂x = exf and ∂f ∂y = xeyf . (c) ∂f ∂x = f and ∂f ∂y = g; ∂g ∂x = g and ∂g ∂y = f. 5. Suppose E → M is a (smooth) vector bundle of rank k over a manifold M. Then E is called trivializable, if it isomorphic to the trivial vector bundle M × Rk → M. 1 2 (a) Show that E → M is trivializable ⇐⇒ E → M admits a global frame, i.e. there exist (smooth) sections s1, ..., sk of E such that s1(x), ..., sk(x) span Ex for any x ∈ M. (b) Show that the tangent bundle of any Lie group G is trivializable. (c) Recall that Rn has the structure of a (not necessarily associative) division algebra over R for n = 1, 2, 4, 8. Use this to show that the tangent bundle of the spheres S1 ⊂ R2 , S3 ⊂ R4 and S7 ⊂ R8 is trivializable.