1/16 Neural Mass model, Jansen and Rit 1995 Andr´es Sandoval Abarca July 12, 2016 2/16 Introduccti´on The Jansen-Rit model is a neural population model of a local cortical circuit. The single area model contains three interconnected neural populations: one for the pyramidal neurons and two for excitatory and inhibitory interneurons forming feedback loops (single area). A multiple area models includes interactions between multiples neural masses. 3/16 Model First each Neural mass has an average membrane potential (state variable) This average membrane potential is the results of different imputs In Neural mass model these imputs represents average pulse density or firing rate, we have that average membrane potential and average pulse densite are the two main quantities of this model. these two quantities are converted via two transformation, the first is a called Post Synaptic Potential function (PSP) and the second is a Potential-to-rate function. 4/16 Model That means, each imput to a Neural mass is converted from an average pulse density via PSP function to an average potential membrane, each of those potential is multiplied by some constants modeling the average number of synapses to the population. Figure: scheme of the transformations 5/16 Model Based in the model of Jansen and Rit the PSP function is a second diferential operator, wich is given by: ∂x ∂t = y ∂y ∂t = Qqz − 2qy − q2 x Here z(t) is the imput to the PSP (firing rate) ,x(t) is the output and the constants depend of the exitatory or inhibitory case Jansen used also the next potential-to-rate function: S(v) = 2e0 (1 + expr(v0−v)) 6/16 Model In this work is we are considering the Neural mass like three blocks: pyramidal neurons, local excitatory and local inhibitory neurons. The scheme is showed in the next figure: Figure: scheme of the single Neural mass model of Jansen 7/16 We have the following O.D.E    ∂2y0(t) ∂t2 = AaS(C2y1(t) − C4y2(t)) − 2a∂y0(t) ∂t −a2 y0(t) ∂2y1(t) ∂t2 = Aa(p/C2 + S(C1y0)) − 2a∂y1(t) ∂t −a2 y1(t) ∂2y2(t) ∂t2 = BbS(C3y0)) − 2b∂y2(t) ∂t − b2 y2(t) A = 3.25, B = 22, C1 = 135, C2 = 0.8C1, C3 = C4 = 0.25C1, e0 = 2.5, v0 = 6, r = 0.56 y p entre 120 y 300. y0, y1 and y2 represening the firing rate of pyramidal, excitatory and inhibitory neurones. 8/16 The Fourier Transform Lemma 1: Let f a periodic function, that is, ∃T > 0 : f(t + T) = f(t)∀t ∈ R then can be written as Fourier’s Series: f(x) = a0 2 + ∞ n=1 ancos(ωnx) + bnsen(ωnx) Con ωn = n2π T , a0, an and bn ∈ R. Note that ω1 = 2π T Definici´on 1: given a function f ∈ L1 (R), We define the Fourier’s Transform of f as the following aplication: {f} : ξ → ˆf(ξ) = R f(x)e−2πiξx dx . 9/16 Lemma 2: Let f a periodic function , then: arg max R+ ˆf(ξ) = ω That’s why we use the Fourier Transform, to get the frequency of the cylcles. Figure: F. Transform of a periodic function 10/16 Some problems not periodic function F.T. 11/16 Solutions I used some literature values of parameters to get periodic oscilations Sometimes I used Matcont to find Hopf Bifurcations Figure: Hopf bifurcation of equilibrium point I moved parameters C, p usually. 12/16 Some frequency Maps With the correct parameters values i got the following Frequency maps: Figure: Frequency maps 13/16 The main idea of all this is to find zones where the frequency change, for example. Figure: Moving A 14/16 Figure: Another Frequency map, changing the p value 15/16 We got a decreasing relation to the frequency Figure: In this case we are moving B 16/16 Coupled system Figure: Phased signales